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Quizzes > High School Quizzes > Science

Acceleration Constant Practice Quiz

Review acceleration principles with engaging practice questions

Difficulty: Moderate
Grade: Grade 10
Study OutcomesCheat Sheet
Paper art representing a physics quiz on constant acceleration for high school students.

Which of the following best describes constant acceleration?
An object's acceleration continuously increases.
An object's velocity increases by equal amounts in equal time intervals.
An object's speed decreases over time.
An object's velocity remains constant.
Constant acceleration means the change in velocity is the same in each equal time interval. This is the defining characteristic of uniform acceleration.
In free fall near Earth's surface, what is the approximate constant acceleration (ignoring air resistance)?
Approximately 3.2 m/s²
Approximately 0 m/s²
Approximately 15.6 m/s²
Approximately 9.8 m/s²
The acceleration due to gravity near Earth is about 9.8 m/s² and remains constant in free-fall conditions (ignoring air resistance). The other values do not represent the typical gravitational acceleration.
What shape is the velocity-time graph of an object moving with constant acceleration?
A horizontal line
An exponential curve
A straight line
A parabola
With constant acceleration, velocity changes linearly with time, producing a straight line on a velocity-time graph. The other graph shapes do not correctly represent this linear relationship.
Which equation correctly describes displacement (s) for an object under constant acceleration, given initial velocity (u), acceleration (a), and time (t)?
s = ut - ½at²
s = ut + at
s = u + at²
s = ut + ½at²
The standard kinematic equation for displacement under constant acceleration is s = ut + ½at². This formulation correctly relates displacement with the initial velocity, constant acceleration, and time.
Which of the following best describes an object in free fall (ignoring air resistance)?
It experiences a constant acceleration downward.
It has a continuously changing acceleration.
It experiences no acceleration.
Its acceleration increases as it falls.
An object in free fall experiences a constant gravitational acceleration, roughly 9.8 m/s² downward. The other choices incorrectly describe the nature of free-fall acceleration.
An object is launched vertically upward. At which points in its trajectory is the acceleration constant (ignoring air resistance)?
At all points in the motion
Only during the descent
Only at the peak of its trajectory
Only at the moment of launch
The acceleration due to gravity remains constant throughout both the upward and downward phases of the motion. This holds true regardless of changes in velocity.
Which of the following scenarios best exemplifies constant acceleration?
A ball in free fall (ignoring air resistance)
An object moving in a circle at constant speed
A rocket launching with varying thrust
A car speeding up and slowing down erratically
A ball in free fall experiences uniform gravitational acceleration, making it a prime example of constant acceleration. The other scenarios involve either variable forces or motions that do not lead to constant linear acceleration.
A ball is dropped from rest and falls under gravity. Which equation correctly gives its velocity after time t?
v = gt²
v = t/g
v = g/t
v = gt
Starting from rest under constant acceleration, the velocity increases linearly with time, following v = gt. The other expressions do not accurately represent the relationship between velocity and time.
For an object accelerating from rest under constant acceleration, what is the shape of its displacement-time graph?
A straight line
A parabola
An exponential curve
A sine wave
The displacement under constant acceleration is given by s = ½at², resulting in a quadratic (parabolic) relationship when plotted against time. A straight line would indicate a linear relationship, which is not the case here.
Which kinematic equation relates velocity squared and displacement without involving time?
v = u + at
v² = u² + 2as
s = ((u+v)/2)*t
s = ut + ½at²
The equation v² = u² + 2as directly relates the velocities and displacement without requiring the time variable. This makes it especially useful when time is not known.
An object thrown upward reaches its highest point. Which of the following is true at that point?
Both velocity and acceleration are zero
Its velocity is zero but acceleration remains -9.8 m/s²
Its velocity is maximum
Its acceleration becomes zero
At the peak of its trajectory, an object momentarily has zero velocity; however, gravity continues to exert a constant acceleration of approximately -9.8 m/s². The other options incorrectly assume that acceleration changes at the peak.
For a car starting from rest and accelerating uniformly, how is velocity related to time?
Velocity is proportional to the square of time
Velocity is directly proportional to time
Velocity remains constant
Velocity is inversely proportional to time
Under constant acceleration from rest, the velocity of the car increases linearly with time according to v = at. This direct proportionality is a key feature of uniform acceleration.
According to Newton's second law, how does increasing the net force affect acceleration if mass remains unchanged?
Acceleration is inversely proportional
Acceleration increases proportionally
Acceleration decreases
Acceleration remains constant
Newton's second law (F = ma) shows that, with a constant mass, acceleration is directly proportional to the net force applied. Increasing the force increases the acceleration by the same proportional factor.
Which equation would you use to calculate displacement if you know an object's initial velocity, constant acceleration, and time of travel?
s = u + at
s = ut + ½at²
s = ut + at
s = vt - ½at²
The displacement equation s = ut + ½at² is the standard formula used for motion under constant acceleration when initial velocity, acceleration, and time are known. The other options are not standard kinematic formulas.
If two objects start from rest and accelerate at 4 m/s², one for 2 seconds and the other for 3 seconds, which covers more distance?
Distance cannot be determined without initial speed
They cover the same distance
The object accelerating for 2 seconds
The object accelerating for 3 seconds
Since displacement from rest under constant acceleration is given by s = ½at², the longer time interval results in a greater distance covered. Thus, the object accelerating for 3 seconds travels farther than the one accelerating for 2 seconds.
For an object starting from rest under constant acceleration, if the time of travel is doubled, how does the displacement change?
It increases by a factor of 2
It increases by a factor of 4
It doubles
It remains the same
Displacement under constant acceleration is proportional to the square of the time (s = ½at²). Doubling the time results in a displacement that is four times greater, not merely double.
Which aspect of motion under constant acceleration is independent of the initial velocity?
The total displacement
The time to reach a certain speed
The final velocity
The constant acceleration value
The constant acceleration is determined by the net force acting on the object and is independent of its initial velocity. Displacement, final velocity, and time all depend on the initial conditions.
As an object ascends with constant acceleration due to gravity, what happens to its speed?
It remains constant
It increases exponentially
It decreases then increases
It decreases linearly with time
When ascending, an object slows down at a constant rate because the gravitational acceleration acts against its motion, leading to a linear decrease in speed over time. The other options do not accurately depict the behavior under constant acceleration.
Which of the following conditions ensures a net constant acceleration on an object?
A constant net force applied in a fixed direction
Forces applied intermittently
Multiple varying forces that average to the same value
Randomly changing forces
A constant net force in a fixed direction directly results in constant acceleration, according to Newton's second law. The other options would lead to variable or unpredictable acceleration.
In a lab experiment, a student plots the displacement of a cart against the square of the time. What should the student observe if the acceleration is constant?
A parabolic curve
A straight line
A horizontal line
A random scatter
For motion under constant acceleration, the equation s = ½at² shows that displacement is directly proportional to the square of time. Plotting s versus t² will yield a straight line, confirming the constant acceleration.
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Study Outcomes

  1. Understand the concept of constant acceleration.
  2. Analyze motion scenarios to determine when acceleration is constant.
  3. Apply kinematic equations to solve problems involving constant acceleration.
  4. Evaluate motion graphs to identify periods of constant acceleration.
  5. Synthesize real-life situations to assess the applicability of constant acceleration principles.

Free: Constant Acceleration Cheat Sheet

  1. Constant acceleration concept - When acceleration is constant, an object's velocity changes by the same amount each second, making its motion predictable and easy to analyze. This steady change is at the heart of many physics problems and even roller‑coaster designs. Ready to see speed shifts on repeat? Foundations of Physics: Constant Acceleration
  2. Master the core kinematic equations - These three formulas link displacement, velocity, acceleration, and time so you can tackle almost any straight‑line motion problem. Knowing which equation to use is like having a secret cheat code for exams. College Physics: Kinematic Equations
  3. Define acceleration - Acceleration is the rate of change of velocity, calculated as a = Δv / t, and tells you how quickly speed is increasing or decreasing. It's measured in meters per second squared (m/s²), so get ready to crunch those Δv's and Δt's. Foundations of Physics: Accelerated Motion
  4. Break down displacement - Displacement (d) is how far and in what direction an object moves from its starting point, found with d = v₀t + ½at² under constant acceleration. Think of it as your motion's GPS coordinate update! University Physics: Motion with Constant Acceleration
  5. Navigate velocity in motion - Velocity (v) tells you both speed and direction, and the final velocity under steady acceleration is v = v₀ + at. It's like checking your speedometer at different times to see how fast you're speeding up. College Physics: Velocity Equations
  6. Problem‑solving practice - Start by listing knowns (v₀, a, t) and unknowns, then pick the equation that plugs right in - no more guesswork. Practicing this stepwise approach builds confidence and cuts down exam jitters. AP Physics: Kinematic Problem Solving
  7. Graph power: area & slope - The area under a velocity‑time graph equals displacement, while the slope of that graph gives you acceleration. Visual learners, this is where your charts become the ultimate study hack! University Physics: Velocity‑Time Graphs
  8. Free‑fall and gravity's pull - In free fall, acceleration due to gravity (g) is a constant 9.8 m/s² downward, so every object "drops" with the same acceleration (ignoring air resistance). It's the ultimate equalizer in physics showdowns! Foundations of Physics: Free Fall
  9. Mnemonic magic - Use VAT (v = v₀ + at), VAD (v² = v₀² + 2ad), and DAT (d = v₀t + ½at²) to recall formulas in a flash. These catchy acronyms stick in your memory and keep exam stress at bay. Constant Acceleration Equations
  10. Real‑world motion detectives - Apply these ideas to calculate stopping distances in cars, analyze ball trajectories in sports, or predict how fast a rocket liftoff is. Bringing theory into the real world makes studying both fun and unforgettable! AP Physics: Real‑World Practice
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